Question

Логарифмичеки уравнения

Answer 1

$-log_3log_3{\sqrt[3]{\sqrt[3]3}} = -log_3\frac{1}{9} = -log_33^{-2} = 2\\\\\sqrt[3]{\sqrt[3]3} = (3^\frac{1}{3})^\frac{1}{3} = 3^\frac{1}{9}\\\\log_3{\sqrt[3]{\sqrt[3]3}}=log_33^\frac{1}{9} = \frac{1}{9} log_33 = \frac{1}{9}$

Ответ: 2