Question

А)(x+4y)(4y-x) b) 2t(t+8)-(t-6)^2 преобразуйте в многочлен стардантного вида

Answer 1

А) (x+4y)(4y-x)=16y^2-x^2
б)2t(t+8)-(t-6)^2=2t^2+16t-(t^2-12t+36)= 2t^2+16t-t^2+12t-36=t^2+28t-36

Answer 2

( Х + 4y )( 4y - x ) = 16y^2 - x^2
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2t( t + 8 ) - ( t - 6 )^2 = 2t^2 + 16t - ( t^2 - 12t + 36 ) = 2t^2 + 16t - t^2 + 12t - 36 = t^2 + 28t - 36