Question

A)2i*z=1 б)(2+i)*z=-i в)(3+i)*z=5-i

Answer 1

1)z=1/2i=i/-2=-i/2
2)z=-i/(2+i)=2(2-i)/(4+1)=2/3*(2-i)
3)z=(5-i)/(3+i)=(5-i)(3-i)/(9+1)=(15-5i-3i+1)/10=(16-8i)/10=1,6-0,8i