X^2+17x+72/x+9=-1
x+17x+72+9=-1
18x=-72-9-1
18x=-90
x=5
Решение
<span>2tgx/(1+tg</span>²<span>x) = cosx
2sinxcosx - cosx = 0
cosx(2sinx - 1) = 0
1) cosx = 0
x = </span>π/2 + πk, k ∈ Z
2) 2sinx - 1 = 0
2sinx = 1
sinx = 1/2
x = (-1)^n arcsin(1/2) + πn, n ∈ Z
<span>x = (-1)^n (</span>π/6)<span> + πn, n ∈ Z</span>
-5(1-x)-4(2-x)=3
раскроем скобки
-5+5x-8+4x = 3
<span>9x-16 = 0 </span>
9x = 16
<span><span>x = 16</span><span>9
</span></span>
Вот этот график................
если это 1/16a^2+1/6ab+1/9b^2 = 0