sin(arcCos 0)=sin(П/2)=1.................................
3cos^2x-5+3sin^2x=3(cos^2x+sin^2x)-5=3-5=-2
<span>а) (х-1)-(3х-4)=17
x-1-3x+4=17
-2x=14
x=-7
б) 2/3(7-2х)= 1/2
14/3-4x/3=1/2
-4x/3=1/2-14/3=3/6-28/6=-25/6
x=-25/6:(-4/3)=25/6*3/4=25/8=3 1/8
в) -4(х-10)=12(х-1)
-4x+40=12x-12
-4x-12x=-12-40
-16x=-52
x=52/16=13/4=3 1/4
в) -4x + 40 =12х-12
-4x-12x=-12-40
-16x=-52
x=52/16=13/4=3 1/4
г) х/4 - х/5 - х/10 = 2</span>
5x/20-4x/20-2x/20=2
-x/20=2
x=2:(-1/20)=-2*20=-40
(3/5)³*(5/3)²=(5/3)^-3 *(5/3)²=(5/3)^-1=3/5=0,6
0,6<1,6
(3/5)³*(5/3)²<1,6