B1 = 5 bn+1 = - 15/bn
b (1+1) = - 15/b1
b2 = - 15/5= - 3
b(2+1) = - 15/b2
b3 = - 15/b2 = - 15/ (- 3) = 5
b(3+1) = - 15/b3
b4 = - 15/b3 = - 15/5 = - 3
b5 = b(4+1) = - 15/b4 = - 15/ (- 3) = 5
b(5+1) = - 15/b5
b6 = - 15/b5 = - 15/5 = -3
2log₄(11-x)≥1 (11-x)>0 x<11
(11-x)²≥4 x²-22x+121-4=x²-22x+117≥0 корни по Виету 9 и 13
(x-9)(x-13)≥0 x<11
←
--------- 9 ----11------- 13------------
+ - +
x∈(-∞;9]
cos^4a+cos^2asin^2a+sin^2a+tg^2a=cos^2a(cos^2a+sin^2a)+sin^2a+tg^2a=
-2х+1=-х-6
-х=-7
х=7
Ответ: 7
<span>2x-x^2 <или= 0
</span>x(2-x) <или= 0
нули функции: х=0 и х=2
Ответ: (-00; 0] U [ 2; +00)