Question

Помогите!!!!!!!!!!!!!Отмечу лучшим

Answer 1

$x^2+y^2=36\\ x^3-y^3=36(x-y)\\\\ x^2+y^2=36\\ (x-y)(x^2+xy+y^2)=36(x-y)\\\\ x^2+y^2=36\\ (x-y)(x^2+xy+y^2-36)=0\\ \\ x=y\\ 2x^2=36\\ x=y=+/-3\sqrt{2} \\\\ xy=0\\ x=0\\ y=-+6$