Question

Разложить на множители. 1)xy+3y+xz+3z 2)25-c² 3)ab²-2abc+ac²

Answer 1

1)xy+3y+xz+3z=y(x+3)+z(x+3)=(x+3)(y+z)
2) $25-c^{2} = 5^{2}-c^{2} =(5-c)(5+c)$
3)$ab^{2} -2abc+ac^{2} =a(b^{2} -2bc+c^{2})=a(b-c)^{2} =a(b-c)(b-c)$

Answer 2

1)xy+3y+xz+3z=y(x+3)+z(x+3)=(x+3)(y+z).
2)25-c²=(5-c)(5+c).
3)ab²-2abc+ac²=a(b²-2bc+c²)=a(b-c)².