=(а²-2а-2а+4-а²)/ (а-2)(а+2) = (4-4а)/(а-2)(а+2) это который в скобке а теперь будем делить
(4-4а)/(а+2)(а-2)* (а²+2а)/(1-а)= 4(1-а)/(а-2)(а+2)*а(а+2)/(1-а)= 4а/(а-2)
![-1 \leq cos(a) \leq 1](https://tex.z-dn.net/?f=-1+%5Cleq+cos%28a%29+%5Cleq+1)
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![-1 \leq cos(a) \leq 1|*(-1)](https://tex.z-dn.net/?f=-1+%5Cleq+cos%28a%29+%5Cleq+1%7C%2A%28-1%29)
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![-1 \leq -cos(a) \leq 1](https://tex.z-dn.net/?f=-1+%5Cleq+-cos%28a%29+%5Cleq+1)
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![-1 \leq -cos(a) \leq 1|*2](https://tex.z-dn.net/?f=-1+%5Cleq+-cos%28a%29+%5Cleq+1%7C%2A2)
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![-2 \leq -2cos(a) \leq 2|+1](https://tex.z-dn.net/?f=-2+%5Cleq+-2cos%28a%29+%5Cleq+2%7C%2B1)
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![-2+1 \leq 1-2cos(a) \leq 2+1](https://tex.z-dn.net/?f=-2%2B1+%5Cleq+1-2cos%28a%29+%5Cleq+2%2B1)
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![-1 \leq 1-2cos(a) \leq 3](https://tex.z-dn.net/?f=-1+%5Cleq+1-2cos%28a%29+%5Cleq+3)
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Найменше значння дорівнює: -1
5м2+6м-5м-6=5м2+м-6
Д=25+24=49
5(х-0,6)(х+0,8)
(м-3)(м+0,8)
__________
5м+1