(х-3)(х²-9)<0
(x-3)(x-3)(x+3)<0
x₁ = 3; х₂ = 3; х₃ = -3
- + +
-----------₀-------------₀------------>x
-3 3
х∈(-∞; -3)
а) Д = 3*3 - 4*(-4)*1 = 9 + 16 = 25 = 5*5
х1,2 = (3 +/- 5)/2
х1 = 4
х2 = -1
б)Д = 11*11 - 4*18*1 = 121 - 72 = 49 = 7*7
х1,2 = (11 +/- 7)/2
х1 = 9
х2 = 2
Нечетная функция когда y(-x)=-y(x)
(-х)²(-ах+2а-6)=<span>-х²(ах+2а-6)
</span><span>-ах+2а-6=-(ах+2а-6)</span>
<span>-ах+2а-6=<span>-ах-2а+6
</span></span><span>2а-6=-2а+6</span>
<span>4а=12
a=3<span /></span>