А)-√(3а²)
б)√b(b-1)²
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3(х²+2ху+у²)=3(х+у)²=3(х+у)(х+у)
При а =-2
<span>D1=а^2-4 (а>=2 и <=-2) </span>
<span>D2=1/4-а (a<=1/4) </span>
<span>ОДЗ a<=-2 </span>
<span>Проверим </span>
<span>Если а=-2. </span>
<span>1)x^2-2x+1=0 </span>
<span>x=1 </span>
<span>2)x^2+x-2=0 </span>
<span>x=1 </span>
<span>x=-2 </span>
<span>Общий корень х=1 при а=-2. </span>
(х-8)²-2х(6-х)²
х²-16х+64-2х*(36-12х+х²)
х²-16х+64-72х+24х²-2х³
25х²-88х+64-2х³
-2х³+25х²-88х+64