Всего слов - 150шестибуквенных слов - 15Р(А)= 15/150 = 0,1<span>Ответ: 0,1.</span>
2х^2-2х+34+6х^2+34х-10=0
8х^2-32х+24=0
а=8 б=-32 с=24
Д=-32^2-4*8*24=1024-768=256
х1=32+√256 /2*8=32+16/16=3
х2=32-√256 /2*8=32-16/16=1
ответ:(1,3)
Находим d: a6=a5+d => -147=-150+d =>d=3;
Решение
<span>S</span>₅ <span>= 1/2(a</span>₁ <span>+ a</span>₅<span>)•5 = 1/2(a</span>₁ <span>+ a</span>₁ <span>+ 4d)•5 = (a</span>₁ <span>+ 2d)•5
</span><span>S</span>₆₋₁₀ <span>= 1/2(a</span>₆ <span>+ a</span>₁₀<span>)•5 = 1/2(a</span>₁ <span>+ 5d + a</span>₁ <span>+ 9d)•5 = (a</span>₁ <span>+ 7d)•5
</span><span>Найдём разность этих сумм, она равна 200
</span><span>5(a</span>₁ <span>+ 2d) - 5(a</span>₁ <span>+ 7d) = 200</span><span>a</span>₁ <span>+ 2d - a</span>₁ <span>- 7d = 40
</span><span>- 5d = 40
</span><span>d = - 8
</span><span>Аналогично найдём разность суммы с 1 по 10 и с 11 по 20
</span><span>10•1/2(а</span>₁ <span>+ а</span>₁₀<span>) - 10•1/2(а</span>₁₁ <span>+ а</span>₂₀<span>) =
</span><span>= 5(a</span>₁ <span>+ a</span>₁ <span>+ 9d) - 5(a</span>₁ <span>+ 10d + a</span>₁ <span>+ 19d) = 5(9d - 29d) =
= 5(- 20d) =</span><span> 5(- 20)*(- 8) = 800
</span><span>Ответ: 800</span>