Question

2x/x-2- 8/x^2-4- 1/x+2 = 2

Answer 1

ОДЗ:
x≠2
x≠-2
$\frac{2x}{x-2}-\frac{8}{(x-2)*(x+2)}-\frac{1}{x+2}=2*(x-2)*(x+2) \\ \\ 2x^2+4x-8-x+2=2x^2-8$
3x=-2|:3
x=$- \frac{2}{3}$
Ответ:$-\frac{2}{3}$