Х-3у=4; ху-6у=1 x=4+3yy(4+3y)-6y=13y^2+4y-6y-1=03y^2-2y-1=0y2=1; y2=-1/3откуда x1=4+3=7; x2=4-1=3<span>ответ: (7;1), (3;-1/3)</span>
<span>1) (1/9+b)^2 =1/81+2/9b+b</span>²<span>
,2) (k/2-t/5)^2=k</span>²/4-kt/5+t²/25<span>
3) (y+3 1/4)^2=y</span>²+6.5y+169/16<span>
4) (4 1/2+t)^2=81/4+9t+t</span>²