A)
lim x->2 (x^2 - 1)(x - 3)(x - 5) = (2^2 - 1)(2 - 3)(2 - 5) =
= (4 - 1)( - 1)(- 3) = 3*3 = 9
b)
lim x->3 (x - 3)/(x^2 - 9) = [ 0 /0 ] = lim x->3 (x - 3) / ((x - 3)(x + 3)) =
= lim x->3 (1 / (x + 3)) ==> 1/6
2a-3b+c= 2* 1.5 - 3* 1.2+ 0.1 = 3 - 3.6+ 0.1=-0.6 + 0.1= -0.5
Решение в файле...................
Y`=(1/(1-3x))`=((1-3x)⁻¹)`=-(1-3x)⁻²*(1-3x)`=-(-3)/(1-3x)²=3/(1-3x)².
X-7x-1/8=4x+3/4. (Дробью)
-6x-1/8=4x+3/4
8(4x+3)=4(-6x-1)
32x+24x=-4-24
56x=-28
X=-28/56
X=-0,5