Limx³(1/x³-5/x²)/x³(1+1/x)=lim(1/x³-5/x²)/(1+1/x)=(0-0)/(1+0)=0/1=0
1/4 x^2 - 4 =0 1/4 (x^2) = 4 x^2=16 x1=4 x2= -4
An=a1+d(n-1),14=18+13d;13d=14-18;13d=-4;d=-4/13.
S=(18+14)*8/2=32*8/2=32*4=128
Х нулевое = -b/2a => х нул. = 4\-1 *2 = -2
y нулевое = ax^2 -(+) bx -(+)c => y нул = - (-2)^2 -4 *(-2) +1 = 5
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