x²-9≠0⇒x²≠9⇒x≠3 их≠-3
D(f)=(∉-∞ -3)∨(3 ∞)
f(0)=(0-1)/0²-9=-1/-9=1/9
f(-1)=(-1-1)/((-1)²-9)=-2/-8=1/4
f(4)=(4-1)/(4²-9)=3/7
x-9=(√x-3)(√x+3), x≥0