Y = x^3 + x
Уравнение касательной:
y = f(x0) + f'(x0)*(x - x0)
f(x0) = f(2) = 2^3 + 2 = 8 + 2 = 10
f'(x) = 3x^2 + 1
f'(x0) = f'(x0) = 3*2^2 + 1 = 12 + 1 = 13
y = 10 + 13*(x - 2) = 13x + 10 - 26 = 13x - 16
(х+6)(15-х)<108
15x-x2+90-x2-108=0
-2x(квадрат) + 15x - 18 = 0 |-1
2x(квадрат) - 15x + 18 = 0
D= 225 - 4x2x18=225-144=81=9(квадрат)
15-9 6
х1= ________ = ___= 1,5
2х2 4
15+9 24
х2=_______= ___=6
2х2 4
Log(5)2.5+Log(5)50=Log(5)(2.5*50)=
=Log(5)125=3
Ответ---------☆☆☆☆☆☆☆-------