<span>1) cos(3arctg(-1/</span>√<span>3))=cos(-3arctg 1/</span>√<span>3)=cos(3arctg 1/</span>√<span>3)=cos(3*</span>π/6)=cos π/2=0.<span>
2) sin(2arctg(-1))=sin(-2arctg 1)=-sin(2arctg 1)=-sin(2*</span>π/4)=-sin π/2=-1.
8*8=64 не хватает
<span>8*6+12*2=48+24=72</span>