B2=-4
b1+b3=10
q=b2/b1
q=-4/10=-2/5 b6=10*-2/5(5)=-64/625
помоему так
4х²+36х+32=0
D=36²-4·4·32=1296-512=784=28²
x=(-36-28)/8=- 8 или х=(-38+28)/8=-5/4
Значит
![4 x^{2} +36x+32=4(x-(-8))\cdot (x-(- \frac{5}{4}))=(x+8)(5x+4), \\ \frac{x+8}{4 x^{2} +36x+32}= \frac{x+8}{(x+8)(5x+4)} = \frac{1}{5x+4}](https://tex.z-dn.net/?f=4+x%5E%7B2%7D+%2B36x%2B32%3D4%28x-%28-8%29%29%5Ccdot+%28x-%28-+%5Cfrac%7B5%7D%7B4%7D%29%29%3D%28x%2B8%29%285x%2B4%29%2C+%5C%5C++%5Cfrac%7Bx%2B8%7D%7B4+x%5E%7B2%7D+%2B36x%2B32%7D%3D+%5Cfrac%7Bx%2B8%7D%7B%28x%2B8%29%285x%2B4%29%7D+%3D+%5Cfrac%7B1%7D%7B5x%2B4%7D++)
Cos(2x+π/2+(x-π²)/x=-sin2x+(x-π²)/x
(-sin2x+(x-π²)/x)`=-2cos2x+(x-x+π²)/x²=-2cos2x+π²)/x²=-2cosπ/6+π²:(π/12)2=
=-2*√3/2+π²*144/π²==-√3+144