Question

Срочно !!! 30 баллов. решите третие задание

Answer 1

$log_{a}b=17\\\\log_{a}\sqrt[6]{ab}=log_{a}a^{\frac{1}{6}}+log_{a}b^{\frac{1}{6}}=\frac{1}{6}\cdot log_{a}a+\frac{1}{6}\cdot log_{a}b=\\\\=\frac{1}{6}\cdot 1+\frac{1}{6}\cdot 17=\frac{18}{6}=3$

Answer 2

㏒a(ab)^1/6 = ㏒a a^1/6 + ㏒a b^1/6 = 1/6+17/6=18/6=3