Question

Найдите p(y)=p1(y)−p2(y) p(y)=p_1(y)-p_2(y)p(y)=p
​1
​​ (y)−p
​2
​​ (y): побыстрей плиз 30 баллов

Answer 1

$1)\; \; p_1(y)-p_2(y)=\\\\=(2y^4+6y-9)-(3y^4-8y+3)=-y^4+14y-12\\\\2)\; \; p_1(y)-p_2(y)=\\\\=(8y^6+7y^3-17)-(8y^6-7y^3+17)=14y^3-34\\\\3)\; \; p_1(y)-p_2(y)=\\\\=(y^3-y+7)-(y^3+3y+14)=-4y-7\\\\4)\; \; p_1(y)-p_2(y)=\\\\=(18-7y^2)-(y^6-y^2-18)=-y^6-6y^2+36$