Question

Найдите корни уровнений

Answer 1

$1) \\ \frac{x^2}{x+6}= \frac{1}{2} ==\ \textgreater \ x \neq -6 \\ \\ 2x^2=x+6 \\ 2x^2-x-6=0 \\ D=1+ 48=49=7^2 \\ x_1=(1+7)/4=2 \\ x_2=(1-7)/4= -\frac{3}{2} \\ \\ 2) \\ \frac{x^2-x}{x+3}= \frac{12}{x+3} ==\ \textgreater \ x \neq -3 \\ \\ \frac{x^2-x}{x+3}- \frac{12}{x+3}=0 \\ \\ x^2-x-12=0 \\ D=1+48=7^2 \\ x_1= \frac{1+7}{2}=4 \\ \\ x_2= \frac{1-7}{2} \neq -3 \\ \\ x=4$