X^2 -5xy+6y^2=0
D=25y^2-6*4y^2=y^2
x1=(5y+y)/2=3y
x2=(5y-y)/2=2y
x1=3y, x2=2y
Prjamaja y = -2x+4 imeet točky perecečenija s koordinatami: X/2,0/ i Y/0,4./
S(XOY) = 0,5.2.4 = 4
а₁= 14, d= -5, S₄₀= ?
S₄₀ = (2а₁ +39d) * 40/ 2 = (2a₁ +39d)*20 = (2*14 +39*(-5)) * 20 = (28 - 195)*20=
=-167*20 = - 3340