![f(\frac{1}{x})=(\frac{1}{x})^{-5}=(x^{-1})^{-5}=x^{5}\\\\f(\frac{1}{x})<9x^{8}*f(x)\\\\x^{5}<9x^{8}*x^{-5}\\\\x^{5}<9x^{3} \\\\x^{5}-9x^{3}<0\\\\x^{3}(x^{2}-9)<0\\\\x^{3}(x-3)(x+3)<0](https://tex.z-dn.net/?f=f%28%5Cfrac%7B1%7D%7Bx%7D%29%3D%28%5Cfrac%7B1%7D%7Bx%7D%29%5E%7B-5%7D%3D%28x%5E%7B-1%7D%29%5E%7B-5%7D%3Dx%5E%7B5%7D%5C%5C%5C%5Cf%28%5Cfrac%7B1%7D%7Bx%7D%29%3C9x%5E%7B8%7D%2Af%28x%29%5C%5C%5C%5Cx%5E%7B5%7D%3C9x%5E%7B8%7D%2Ax%5E%7B-5%7D%5C%5C%5C%5Cx%5E%7B5%7D%3C9x%5E%7B3%7D+%5C%5C%5C%5Cx%5E%7B5%7D-9x%5E%7B3%7D%3C0%5C%5C%5C%5Cx%5E%7B3%7D%28x%5E%7B2%7D-9%29%3C0%5C%5C%5C%5Cx%5E%7B3%7D%28x-3%29%28x%2B3%29%3C0)
- + - +
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- 3 0 3
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x ∈ (- ∞ ; - 3) ∪ (0 ; 3)
9m^2-n^2/n^2 × 1/15m+n=(9m^2-n^2)×1/n^2 (15m+m)=(9m^2-n^2)/n^2×16m=9m^2-n^2/16mn^2
4x-1←5x-11
4x-5x←-11+1
-x←-10 \:(-1)
x→10
Решение во вложении
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