Question

Помогите, с решением надо))
все номераа)) пж)) кроме а))

Answer 1

$\sqrt{6} *7* \sqrt{6*9} = \sqrt{36} *7* \sqrt{9} =6*7*3=126$, ($\sqrt{2* 9^{2} } -10 \sqrt{2}$)*$\sqrt{2}$=$\sqrt{2*2} (9-10)=2*(-1)$=-2,$(3* \sqrt{2* 7^{2} }- \sqrt{2* 8^{2} }): \sqrt{2}= \sqrt{2}(3*7-8): \sqrt{2}=21-8=13$, $4- \sqrt{5t}- \sqrt{9*80t/16} -12* \sqrt{5t*25} /3=4 \sqrt{5x} - \sqrt{45t} -5*4 \sqrt{5t} = 4\sqrt{5t} - \sqrt{9*5t} -5*4 \sqrt{5t} =4 \sqrt{5t} -3 \sqrt{5t} -20 \sqrt{5t} = \sqrt{5t} (4-3-20)=-19 \sqrt{5t}$