-7-10х+12=-2
-7-10х+12+2= -10х=7 => х=-0.7
2(c + d)/(c - d)
c=3,7 и d=1 2/5 = 1,4
2·(3,7 + 1,4)/(3,7 - 1,4) = 2·5,1/2,3 = 2·51/23 = 102/23 = 4 10/23
(m-5)^2=m^2-10m+25
(-m+5)^2=m^2-10m+25
(-m-5)^2=m^2 +10m+25
(c^3-1)^2=c^6-2c^3+1
(p^3-q^3)^2=p^6-2p^3q^3+q^6
(x^2-y)^2=x^4-2x^2y+y^2
(a^2-1)^2=a^4-2a^2+1
Решение:
1) 1/(х-1) + 1/(х-1)*(х+1) = 5/8
2) х+1 +1/ (х-1) * (х +1) = 5/8
3) (х+2) * 8 = 5*( х+1)* (х - 1)
4) 8х + 16 = 5 (х^2 -1)
5) 8х + 16 = 5х^2 -5
-5х^2 +8х +21 = 0
D = 64 - 4*(-5)*21 = 484
x1 = -8 + 22/ -10 = -1,4
х2 = -8 - 22/ -10 = 3
Ответ: Х1 = -1,4; Х2 = 3;