<span>(2+1)(2^2+1)(2^4+1)(2^8+1)-2^16=3*5*17*257-65536=-1
</span>
<span>3(2^2+1)(2^8+1)(2^16+1)(2^32+1)-256^8=3*5*257*65537*4294967297-18446744073709551616= - 17361641481138401521
</span>
<span>8(3^2+1)(3^4+1)(3^8+1)(3^16+1)-81^8=8*10*82*6562*43046722-1853020188851841= - 1
</span>
<span>156•161•166-159•(161•163-20)=4169256-4169457= - 201
</span>
<span>2009^4-2008•2010•(2009^2+1)=16289949838561-4036080*4036082=1
</span>
<span>1997•2004•2011-2003(2005•2004+1)+49•2004=8047997868-8048096063+98196=1</span>
По дискриминанту = b^2-4ac=9+28=√37
x1,= (-3+√37)/2
x2=(-3-√37)/2
x1+x2= дальше прикрепляю рисунок
(a+2)*96 / 2(a-4)*a(a+2)=
=48/a(a-4)
(3a/a-4) - (48/a(a-4) =
=(3a²-48)/a(a-4) =
= 3(a²-16)/a(a-4) =
= 3(a-4)(a+4) /a(a-4) =
=3(a+4)/a