<span>Ответ нет, так как сумма квадратов двух чисел больше 0
можем проверить:
(x-3)²+(y+7)²<-4
х=2; у=-5
</span><span>(2-3)²+(-5+7)²<-4
</span><span>(-1)²+(2)²<-4
1 + 4 < -4
5 < -4 не верно</span>
67..... Не знаю... Вроде да
Решение во вложении.................ф
Объяснение:
![1)\; \; \frac{2(1-4a)}{2a+1}\geq -6\; \; \to \; \; \; \frac{1-4a}{2a+1}\geq -3\; \; ,\; \; \frac{1-4a}{2a+1}+3\geq 0\; \; ,\\\\\frac{1-4a+6a+3}{2a+1}\geq 0\; \; ,\; \; \frac{2a+4}{2a+1}\geq 0\; \; ,\; \; \frac{2(a+2)}{2a+1}\geq 0\; \; ,\\\\a+2=0\; \; \to \; \; a_1=-2\\\\2a+1=0\; \; \to \; \; a_2=-\frac{1}{2}\\\\znaki:\; \; \; +++[-2\, ]---(-\frac{1}{2})+++\\\\a\in (-\infty ,-2\, ]\cup (-\frac{1}{2},+\infty )](https://tex.z-dn.net/?f=1%29%5C%3B%20%5C%3B%20%5Cfrac%7B2%281-4a%29%7D%7B2a%2B1%7D%5Cgeq%20-6%5C%3B%20%5C%3B%20%5Cto%20%5C%3B%20%5C%3B%20%5C%3B%20%20%5Cfrac%7B1-4a%7D%7B2a%2B1%7D%5Cgeq%20-3%5C%3B%20%5C%3B%20%2C%5C%3B%20%5C%3B%20%5Cfrac%7B1-4a%7D%7B2a%2B1%7D%2B3%5Cgeq%200%5C%3B%20%5C%3B%20%2C%5C%5C%5C%5C%5Cfrac%7B1-4a%2B6a%2B3%7D%7B2a%2B1%7D%5Cgeq%200%5C%3B%20%5C%3B%20%2C%5C%3B%20%5C%3B%20%5Cfrac%7B2a%2B4%7D%7B2a%2B1%7D%5Cgeq%200%5C%3B%20%5C%3B%20%2C%5C%3B%20%5C%3B%20%5Cfrac%7B2%28a%2B2%29%7D%7B2a%2B1%7D%5Cgeq%200%5C%3B%20%5C%3B%20%2C%5C%5C%5C%5Ca%2B2%3D0%5C%3B%20%5C%3B%20%5Cto%20%5C%3B%20%5C%3B%20a_1%3D-2%5C%5C%5C%5C2a%2B1%3D0%5C%3B%20%5C%3B%20%5Cto%20%5C%3B%20%5C%3B%20a_2%3D-%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5Cznaki%3A%5C%3B%20%5C%3B%20%5C%3B%20%2B%2B%2B%5B-2%5C%2C%20%5D---%28-%5Cfrac%7B1%7D%7B2%7D%29%2B%2B%2B%5C%5C%5C%5Ca%5Cin%20%28-%5Cinfty%20%2C-2%5C%2C%20%5D%5Ccup%20%28-%5Cfrac%7B1%7D%7B2%7D%2C%2B%5Cinfty%20%29)
![2)\; \; \frac{x+2y}{4}-\frac{x-2y}{2}-\frac{7-2y}{3}=1-x\; \Big |\cdot 12\\\\3(x+2y)-6(x-2y)-4(7-2y)=12(1-x)\\\\3x+6y-6x+12y-28+8y=12-12x\\\\9x+26y=40\; \; (\star )](https://tex.z-dn.net/?f=2%29%5C%3B%20%5C%3B%20%5Cfrac%7Bx%2B2y%7D%7B4%7D-%5Cfrac%7Bx-2y%7D%7B2%7D-%5Cfrac%7B7-2y%7D%7B3%7D%3D1-x%5C%3B%20%5CBig%20%7C%5Ccdot%2012%5C%5C%5C%5C3%28x%2B2y%29-6%28x-2y%29-4%287-2y%29%3D12%281-x%29%5C%5C%5C%5C3x%2B6y-6x%2B12y-28%2B8y%3D12-12x%5C%5C%5C%5C9x%2B26y%3D40%5C%3B%20%5C%3B%20%28%5Cstar%20%29)
Уравнение можно решить в целых числах, т.к. коэффициенты 9 и 26 - взаимно простые.
![x_0=-10\; \; ,\; \; y_0=5\; \; \Rightarrow \; \; \; 9\cdot (-10)+26\cdot 5=40\; \; (\star \star )\\\\(\star)-(\star \star )\; :\; \; \; 9(x+10)+26(y-5)=0\; \; \Rightarrow \\\\x+10=-\frac{26(y-5)}{9}\; \; \Rightarrow \; \; y-5=9k\; ,\; k\in Z\\\\y=9k+5\\\\x+10=-26k\; \; \Rightarrow \; \; \; x=-26k-10\; ,\; k\in Z\\\\Otvet:\; \; \left \{ {{x=-26k-10\; ,\; k\in Z} \atop {y=9k+5\; ,\; k\in Z}} \right.](https://tex.z-dn.net/?f=x_0%3D-10%5C%3B%20%5C%3B%20%2C%5C%3B%20%5C%3B%20y_0%3D5%5C%3B%20%5C%3B%20%5CRightarrow%20%5C%3B%20%5C%3B%20%5C%3B%209%5Ccdot%20%28-10%29%2B26%5Ccdot%205%3D40%5C%3B%20%5C%3B%20%28%5Cstar%20%5Cstar%20%29%5C%5C%5C%5C%28%5Cstar%29-%28%5Cstar%20%5Cstar%20%29%5C%3B%20%3A%5C%3B%20%5C%3B%20%5C%3B%209%28x%2B10%29%2B26%28y-5%29%3D0%5C%3B%20%5C%3B%20%5CRightarrow%20%5C%5C%5C%5Cx%2B10%3D-%5Cfrac%7B26%28y-5%29%7D%7B9%7D%5C%3B%20%5C%3B%20%5CRightarrow%20%5C%3B%20%5C%3B%20y-5%3D9k%5C%3B%20%2C%5C%3B%20k%5Cin%20Z%5C%5C%5C%5Cy%3D9k%2B5%5C%5C%5C%5Cx%2B10%3D-26k%5C%3B%20%5C%3B%20%5CRightarrow%20%5C%3B%20%5C%3B%20%5C%3B%20x%3D-26k-10%5C%3B%20%2C%5C%3B%20k%5Cin%20Z%5C%5C%5C%5COtvet%3A%5C%3B%20%5C%3B%20%5Cleft%20%5C%7B%20%7B%7Bx%3D-26k-10%5C%3B%20%2C%5C%3B%20k%5Cin%20Z%7D%20%5Catop%20%7By%3D9k%2B5%5C%3B%20%2C%5C%3B%20k%5Cin%20Z%7D%7D%20%5Cright.)
![3)\; \; \left\{\begin{array}{ccc}3x+2>x-2\\x+15>6-2x\\x-14<5x+14\end{array}\right\; \; \left\{\begin{array}{ccc}2x>-4\\3x>-9\\-28<4x\end{array}\right\; \; \left\{\begin{array}{ccc}x>-2\\x>-3\\x>-7\end{array}\right\; \; \Rightarrow \; \; x>-2\\\\\\x\in (-2,+\infty )](https://tex.z-dn.net/?f=3%29%5C%3B%20%5C%3B%20%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7D3x%2B2%3Ex-2%5C%5Cx%2B15%3E6-2x%5C%5Cx-14%3C5x%2B14%5Cend%7Barray%7D%5Cright%5C%3B%20%5C%3B%20%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7D2x%3E-4%5C%5C3x%3E-9%5C%5C-28%3C4x%5Cend%7Barray%7D%5Cright%5C%3B%20%5C%3B%20%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Dx%3E-2%5C%5Cx%3E-3%5C%5Cx%3E-7%5Cend%7Barray%7D%5Cright%5C%3B%20%5C%3B%20%5CRightarrow%20%5C%3B%20%5C%3B%20x%3E-2%5C%5C%5C%5C%5C%5Cx%5Cin%20%28-2%2C%2B%5Cinfty%20%29)
Вот такое решкние:
X=1 или х= - 1