Question

Решите уравнение пожалуйстаа 3/(x^2-6x+9)=1/(x+3)+6/(9-x^2))

Answer 1

3                                  1                                  6

__________=________________  - ___________

(х-3)²                          х+3                       (х-3)(х+3)

3(х+3)=(х-3)² -6(х-3)

3х+9-х²+6х-9+6х-18=0

-х²+9х-18=0

х²-9х+18=0

Д=81-72=9

х1=(9+3+/2=6

х2=(9-3)/2=3  ОДЗ х≠3 х≠-3

ответ х=6