∫sin(3x+π/6)dx обозначим 3х+π/6 = t 3dx=dt dx=dt/3
∫sint*dt/3=-1/3*cost+c=-1/3cos(3x+π/6)+c
Sin^2x+cos (x) + 2=n^2sxi+cos (x) +2
<span>2sin²(П/2-x)+√2*cosx=0
2cos²x+√2cosx=0
cosx(2cosx+√2)=0
cosx=0 2cosx+√2=0
<u>x=π/2+πn, n∈Z </u> cosx=-√2/2
<u> x=+-3π/4+2πn, n∈Z</u></span>