Решение во вложенииииииииииииииииииииииииии
<span>X^2-6X+10>0
х</span>²-6х+10=0
<span>D<0 - корней нет
х</span>∈R
<span>х - любое число
</span>
64х^3+144х^2+108х+27=0
64х^3+48х^2+96х^2+72х+36х+27=0
16х^2*(4х+3)+24х*(4х+3)+9*(4х+3)=0
(4х+3)*(16х^2+24х+9)=0
(4х+3)*(4х+3)^2=0
(4х+3)^3=0
4х+3=0
4х=-3
х=-3/4=-0,75
(3X^6)^3=3X^18
(X^4)^7=X^28
4B^2*C*(-2.5BC^4)=-10B^3*C^5
(-2X^10*Y^6)^4=16X^20*Y^12
64 =4*4*4=4³
log9 log4 16 =log9 3=1/2
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log9 16 - log27 8 =log3² 4² - log3³ 2³ =log3 4 -log3 2 =log3 (4/2) =log3 2
3^ (log3 2)=2^(log3 3) =2