Область определения функции
![\sin x\ne 0;\,\,\,\,\,\,\,\,\,\,\, x\ne \pi k,k \in Z\\ \cos x\ne 0;\,\,\,\,\,\,\,\,\,\,\,x\ne \frac{\pi}{2} + \pi n,n \in Z](https://tex.z-dn.net/?f=%5Csin+x%5Cne+0%3B%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C+x%5Cne++%5Cpi+k%2Ck+%5Cin+Z%5C%5C+%5Ccos+x%5Cne+0%3B%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2Cx%5Cne+%5Cfrac%7B%5Cpi%7D%7B2%7D+%2B+%5Cpi+n%2Cn+%5Cin+Z)
В этих точках функция имеет разрыв
Упростим нашу функцию
![y=\underbrace{tgx\cdot ctgx}_{1}+\sin x=1+\sin x](https://tex.z-dn.net/?f=y%3D%5Cunderbrace%7Btgx%5Ccdot+ctgx%7D_%7B1%7D%2B%5Csin+x%3D1%2B%5Csin+x)
Строим сначала функцию
![y=\sin x](https://tex.z-dn.net/?f=y%3D%5Csin+x)
, затем поднимем на 1 ед. вверх, получаем искомый график функции
![y=\sin x+1](https://tex.z-dn.net/?f=y%3D%5Csin+x%2B1)
(4a-b)²=(4a)²-2*4a*b+b²=16a²-8ab+b²
(4a-b)³=(4a)³-3*(4a)²*b+3*4a*b²-b³=64a³-48a²b+12ab²-b³
(4a+b)³=(4a)³+3*(4a)²*b+3*4a*b²+b³=64a³+48a²b+12ab²+b³