<span> sinx =0</span>⇒х=πп⇒х=0,х=π,х=2π
Найдём производную от функции. Приравняем к нулю. Найдём точки максимума и минимума
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0,01ab × 100a = a²b
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127у = 139
у = 139/127
х = (13 - 8у) : 7
х = (13 -1112/127 ) : 7
х = 539/127 :7
х = 77/127