<span>Ответ:(-∞;-5)Ụ(5;∞)</span><span />
A)(2x-3)²-3=(2x+1)²-11
4x²-12x+9-3=4x²+4x+1-11
4x²-12x-4x²-4x=1-11-9+3
-16x=-16
x=1
б)16y²-(4y-3)²=15y-90
16y²-16y²+24y-9=15y-90
16y²-16y²+24y-15y=-90+9
9y=-81
y=-9
в)3(x-1)²-(2-x)(2+x)=(2x-1)²
3x²-6x+3-4+x²=4x²-4x+1
3x²-6x+x²-4x²+4x=1-3+4
-2x=2
x=-1
(х+4)х-(х-3)(х+7) = х²+4х-х²-7х+3х+21 = 21
0,18х-36-0,78х=120; 0,18х-0,78х=120+36; -0,6х=156; х=260
А). (2а+2b)(a-b)=2(a+b)(a-b)=2(a²-b²)= 2a²-2b²
б). (x-y)(5x+5y)=5(x-y)(x+y)=5(x²-y²)= 5x²-5y²
в). (4a+4c)(a+c)= 4(a+c)(a+c)=4(a²+c²)=4a²+4c²
г). (3a-3x)(7a-7x)=3(a-x)7(a-x)=(3a²-x²)(7a²-x²)