Question

Система во вложении :)

Answer 1

Y=3-x
$3^{x}+ 3^{(3-x)}=12|* 3^{x} \\ 3^{2x}+ 3^{3}-12* 3^{x}=0 \\ 3^{x}=t$
t²+27-12t=0|:3
t²-12t+27=0
По теореме Вието
t1+t2=-(-12)=12
t1*t2=27
t1=9
t2=3
$3^{x}=9=3^{2} \\ x_{1}=2$
$3^{x}=3=3^{1} \\ x_{2} =1$
$y_{1}=3- x_{1} \\ y_{1}=3-2 \\ y_{1}=1 \\ y_{2}=3- x_{2} \\ y_{2}=3-1 \\ y_{2}=2$