Question

Разложи на множители: s^3−s^2x−sx^2+x^3

Answer 1

S³-s²x-sx²+x³=s³+x³-sx(s+x)=(s+x)(s²-sx+x²)=(s+x)(s²-sx+x²-sx)=
=(s+x)(s²-2sx+x²)=(s+x)(s-x)².