( 3 - /!2 )^2 = 9 - 6/!2 + 2 =11 -6/!2.
( /!5 -2) (/!5 + 2 ) = 5 - 4 =1
{2x+3y=3 I (домножаем)5 {10x+15y=15 {23y=-23 {y=-1
{5x-4y=19 I (домножаем)-2 {-10x+8y=-38 {10x+15y=15 {10x+15(-1)=15
10x=30 x=3
{x=3
<span>{y=-1</span>
вооот. последнее не точно)...............................
![16log_4(5- \sqrt{5})+4log_2( \sqrt{5}+5)= \frac{16}{2}log_2(5- \sqrt{5})+4log_2(5+ \sqrt{5})=\\\\=8log_2(5- \sqrt{5})+4log_2(5+ \sqrt{5})](https://tex.z-dn.net/?f=16log_4%285-+%5Csqrt%7B5%7D%29%2B4log_2%28+%5Csqrt%7B5%7D%2B5%29%3D+%5Cfrac%7B16%7D%7B2%7Dlog_2%285-+%5Csqrt%7B5%7D%29%2B4log_2%285%2B+%5Csqrt%7B5%7D%29%3D%5C%5C%5C%5C%3D8log_2%285-+%5Csqrt%7B5%7D%29%2B4log_2%285%2B+%5Csqrt%7B5%7D%29)
! В задании скрывается ошибка. Скорее всего там 16 и 4 стоят в степенях
![16^{log_4(5- \sqrt{5})}+4^{log_2( \sqrt{5}+5)}=4^{2log_4(5- \sqrt{5})}+2^{2log_2( \sqrt{5}+5)}=\\\\=(5- \sqrt{5})^2+( \sqrt{5}+5)^2=25+5-10 \sqrt{5}+5+25+10 \sqrt{5}=60](https://tex.z-dn.net/?f=16%5E%7Blog_4%285-+%5Csqrt%7B5%7D%29%7D%2B4%5E%7Blog_2%28+%5Csqrt%7B5%7D%2B5%29%7D%3D4%5E%7B2log_4%285-+%5Csqrt%7B5%7D%29%7D%2B2%5E%7B2log_2%28+%5Csqrt%7B5%7D%2B5%29%7D%3D%5C%5C%5C%5C%3D%285-+%5Csqrt%7B5%7D%29%5E2%2B%28+%5Csqrt%7B5%7D%2B5%29%5E2%3D25%2B5-10+%5Csqrt%7B5%7D%2B5%2B25%2B10+%5Csqrt%7B5%7D%3D60++++++++)
X²+(1-x)(1-3x)=x²+1-3x-x+3x²=4x²-4x+1
4x²-4x+1
где a=4 b=-4 с=1
D= b²-4ac=16-4*4=16-16=0
=> x=-b/2a=4/2*4=4/8=0,5