Question

Алгебра 9 класс, задание во вложении.Желательно решение на рисунке.Заранее спасибо

Answer 1

1)
б) $\left \{ {{2x \geq -7} \atop {x\ \textless \ 5}} \right. \\ \left \{ {{x \geq -3.5} \atop {x\ \textless \ 5}} \right.$
в) $\left \{ {{3t+4\ \textless \ 0} \atop {2t+8 \geq 0}} \right. \\ \left \{ {{3t\ \textless \ -4} \atop {2t \geq -8}} \right. \\ \left \{ {{t\ \textless \ -4/3} \atop {t \geq -4}} \right.$

а)(-∞:-4) U [1;+∞)
б)[-3.5;5)
в)[-4;-4/3)

2)$\left \{ {{3x-6 \leq 0} \atop {2 x^{2} +5x+2\ \textgreater \ 0}} \right. \\ \left \{ {{3x \leq 6} \atop {2 x^{2} +5x+2\ \textgreater \ 0}} \right. \\ \left \{ {{x \leq 2} \atop {2 x^{2} +5x+2\ \textgreater \ 0}} \right. \\ 2 x^{2} +5x+2\ \textgreater \ 0 =\ \textgreater \ x_{1} =-0.5 ; x_{2} =-2 \\ 2(x+0.5)(x+2) \\ 2x+1+2x+4 \\ 4x+5 \\ 4x=-5 \\ x=-1.25 \\ \left \{ {{x \leq 2} \atop {x\ \textgreater \ -1.25}} \right.$

(-1.25;2]

$\left \{ {{3 x^{2} \geq 108} \atop { x^{2} +9x+8\ \textless \ 0}} \right. \left \{ {{ x^{2} \geq 36} \atop {x^{2} +9x+8\ \textless \ 0}} \right. \left \{ {{x \geq 6} \atop {x^{2} +9x+8\ \textless \ 0}} \right. \\ x^{2} +9x+8\ \textless \ 0 \\ 1(x+8)(x+1) \\ x+8+x+1 \\ 2x=9 \\ x=4.5 \\ \left \{ {{x \geq 6} \atop {x\ \textless \ 4.5}} \right.$

(-∞;4.5)U[6;+∞)