6 и -3....................
Задачу решил, ответ можете увидеть во вложении.
![\left \{ {{y=x+4} \atop {x^{2}+(x+4)^{2}}=16 } \right. \\\\\left \{ {{y=x+4} \atop {x^{2}+ x^{2}+8x+16}=16} \right.\\\\\left \{ {{y=x+4} \atop {2x^{2}+8x=0} } \right.\\\\\left \{ {{y=x+4} \atop {2x(x+4)=0}} \right.\\\\\left \{ {{x_{1}=0} \atop {y_{1}=4} } \right. \\\\\left \{ {{x_{2}=-4} \atop {y_{2}=0 } \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7By%3Dx%2B4%7D%20%5Catop%20%7Bx%5E%7B2%7D%2B%28x%2B4%29%5E%7B2%7D%7D%3D16%20%7D%20%5Cright.%20%5C%5C%5C%5C%5Cleft%20%5C%7B%20%7B%7By%3Dx%2B4%7D%20%5Catop%20%7Bx%5E%7B2%7D%2B%20x%5E%7B2%7D%2B8x%2B16%7D%3D16%7D%20%5Cright.%5C%5C%5C%5C%5Cleft%20%5C%7B%20%7B%7By%3Dx%2B4%7D%20%5Catop%20%7B2x%5E%7B2%7D%2B8x%3D0%7D%20%7D%20%5Cright.%5C%5C%5C%5C%5Cleft%20%5C%7B%20%7B%7By%3Dx%2B4%7D%20%5Catop%20%7B2x%28x%2B4%29%3D0%7D%7D%20%5Cright.%5C%5C%5C%5C%5Cleft%20%5C%7B%20%7B%7Bx_%7B1%7D%3D0%7D%20%5Catop%20%7By_%7B1%7D%3D4%7D%20%7D%20%5Cright.%20%5C%5C%5C%5C%5Cleft%20%5C%7B%20%7B%7Bx_%7B2%7D%3D-4%7D%20%5Catop%20%7By_%7B2%7D%3D0%20%7D%20%5Cright.)
Ответ : два решения (0 ; 4) , ( - 4 , 0)
A25=a1+24d
d=a2-a1=-6-(-3)=-3
d=-3
a25=(-3)+24×(-3)=(-3)+(-72)=(-75)
Найти число х по его логарифму:
<span>Log61(x)=log61lg1000 + log61(17)
</span>Log61(x)=log61(3) + <span>log61(17)
</span>Log61(x)=log61(3 * 17)
x = 51