[tex] \left \{ {{7х+4у=5} \atop {3x+2у=3умнажаем (-2[tex] \left \{ {{7х+ 4y=5} \atop {- 6х - 4у=- 6}} \right. х = -1; у = 3
X2-y2=8
х=4-у
16-8у+у2-y2=8
х=4-у
16-8у=8
х=4-у
8у=8
х=4-у
у=1
х=3
√3-√2=1/(√3+√2)
(√3+√2)^(x-3)≤(√3+√2)^√(x+3)
√3+√2>1⇒x-3≤√(x+3)
{x+3≥0⇒x≥-3
{x²-6x+9≤x+3
x²-7x+6≤0
x1+x2=7 U x1*x2=6
x1=1 U x2=6
x∈[1;6]