Ответ:
sin^2x+sin2x=1
sin^2x+2sinxcosx-1=0
sin^2x+2sinxcosx-sin^2x-cos^2x=0
2sinxcosx-cos^2x=0
cosx(2sinx-cosx)=0
1)cosx=0,x=π/2+πk,k-Z
2)2sinx-cosx=0
2sinx=cosx |:cosx
2tgx=1
tgx=1/2
x=arctg1/2+πn,n-Z
y³-3y²+9y+3y²-9y+27-y³+6y = 0
6y+27 = 0
6y = -27
y = -27/6 = -9/2
y = -4.5