X/(x³+1)-1/(x²-x+1)=1/7
x/[(x+1)*(x²-x+1)]-1/(x²-x+1)=1/7
[x-(x+1)]/[(x+1)*(x²-x+1)]=1/7
-1/[(x+1)*(x²-x+1)]=1/7. пропорция
-7=(x+1)*(x²-x+1), x³+1=-7, x³+8=0
x³=-8, x=-2
<u>ответ: x=-2</u>
1. у=х²-12х+1
х0=-b/2a=12/2=6
y0=6²-12*6+1=-35.
ветви вверх
2. у=х²-8х+3
х0=8/2=4
у0=4²-8*4+3=-13
ветви вверх
<span>х-(50-х)=12</span>
х-50+х=12
х+х=12+50
2х=62/2
х=31
2.<span>х+(х+1)+(х+2)=9</span>
<span>х+х+1+х+2=9</span>
<span>3х=-1+9</span>
<span>3х=8/3</span>
<span>х=3/8</span>
<span>3.</span>
0,08 вот это точно так в квадрате