(3cos(π-β)+sin(π/2+β))/cos(β+3π)=
=(3·(-cosβ)+cosβ)/cos(β+π+2π)=
=-2cosβ/(-cosβ)=-2;
используемые формулы:
cos(π-β)=-cosβ;
sin(π/2+β)=cosβ;
cos(π+β)=-cosβ;
cos(2π+β)=cosβ;
1) (а+4)² 2) =(3х-1)² 3) =(11m-4n)² 4) =(6a+2b)² 4)=( (a³-2b)²
6) =(5p^5+g^4)² 7) =(1/13x²+13y²)² 8) =(3/8n³+4mn²)²
1) f(3,6)>f(1,8)
2)f(-1,7)>f(-2,5)
3)f(-5,4)4)f(0,9)>f(-0,2)