Question

Алгебра 4.8 помагите пожалуйста ​

Answer 1

$1)(b^{5})^{3} \times( {b}^{2} )^{7} \div ( {b}^{6})^{4} \\ {b}^{15} \times {b}^{14} \div {b}^{24} = {b}^{15 + 14} \div {b}^{24} = \\ = {b}^{29} \div {b}^{24} = {b}^{29 - 24} = {b}^{5} \\ ( - 2)^{5} = - 32 \\ \\ 2) ({a}^{2} )^{5} \times ({a}^{10})^{2} \div ({a}^{14})^{2} \\ {a}^{10} \times {a}^{20} \div {a}^{28} = \\ = {a}^{10 + 20} \div {a}^{28} \\ {a}^{30} \div {a}^{28} = {a}^{30 - 28} = {a}^{2} \\ ( - \frac{3}{7})^{2} = \frac{9}{49}$