Решение
Sin (-11пи/4) = - sin[(12π/4) - π/4] = - sin(3π - π/4) = - sin(π/4) = - √2/2
<span>tg 17пи /6 = tg[(18</span>π/6) - π/6)] = tg(3π - π/6) = - tg(π/6) = - 1/√3
У=-4 0,5Х-4-2=-4
у=1
вот все решение
а) 6x+3x^3y-12xy^2= 3x(2+x^2y-12y^2)
b) 54a-103a+102a= a(54-103+102)