Question

. Решите неравенство методом интервалов 6x+18/7x≤0

Answer 1

6x+18/7x≤0
6(x+3)/7x ≤ 0
$\left \{ {{6(x+3) \leq 0} \atop {7x\ \textgreater \ 0}} \right.$
$\left \{ {{6(x+3) \geq 0} \atop {7x\ \textless \ 0}} \right.$
$\left \{ {{ x \leq -3} \atop {x\ \textgreater \ 0}} \right.$
$\left \{ {{x \geq -3} \atop {x\ \textless \ 0}} \right.$
x∈Ф
x∈[-3;0)