Подходят два
Б) (a^(4,5)-2b^2)(a^(4,5)+2b^2)
В) (a-2b^4)(a+2b^4)
<span>х4+х3+6х2+5х+5=x2(x2+x+1)+5(x2+x+1)=(x2+5)(x2+x+1)</span>
![\sqrt{3}\cos^2x=\sin x\cos x\\ \\ \cos x(\sqrt{3}\cos x-\sin x)=0](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D%5Ccos%5E2x%3D%5Csin%20x%5Ccos%20x%5C%5C%20%5C%5C%20%5Ccos%20x%28%5Csqrt%7B3%7D%5Ccos%20x-%5Csin%20x%29%3D0)
Произведение двух множителей равно нолю, значит
![\cos x=0~~~\Longrightarrow~~~~ \boxed{x_1=\frac{\pi}{2}+\pi n,n \in \mathbb{Z}}\\ \\ \sqrt{3}\cos x-\sin x=0~~~|:\cos x\ne0\\ \\ \sqrt{3}-{\rm tg}\, x=0\\ \\ {\rm tg}\, x=\sqrt{3}~~~~\Rightarrow~~~~ \boxed{x_2=\frac{\pi}{3}+\pi n,n \in \mathbb{Z}}](https://tex.z-dn.net/?f=%5Ccos%20x%3D0~~~%5CLongrightarrow~~~~%20%5Cboxed%7Bx_1%3D%5Cfrac%7B%5Cpi%7D%7B2%7D%2B%5Cpi%20n%2Cn%20%5Cin%20%5Cmathbb%7BZ%7D%7D%5C%5C%20%5C%5C%20%5Csqrt%7B3%7D%5Ccos%20x-%5Csin%20x%3D0~~~%7C%3A%5Ccos%20x%5Cne0%5C%5C%20%5C%5C%20%5Csqrt%7B3%7D-%7B%5Crm%20tg%7D%5C%2C%20x%3D0%5C%5C%20%5C%5C%20%7B%5Crm%20tg%7D%5C%2C%20x%3D%5Csqrt%7B3%7D~~~~%5CRightarrow~~~~%20%5Cboxed%7Bx_2%3D%5Cfrac%7B%5Cpi%7D%7B3%7D%2B%5Cpi%20n%2Cn%20%5Cin%20%5Cmathbb%7BZ%7D%7D)
Log₀,₂₅(5x+36)=-2;(5x+36)>0 ⇒(1/4)⁻²=5x+36;⇒
4²=5x+36;⇒5x=16-36=-20;
x=-4;