4k^2-p^2=(2k-p)(2k+p)
(p-2k)(-p-2k)/(p-2k)^2=2k+p/2k-p
Берем производную: S'(t) = 2t - 3
приравниваем к 5: 2t - 3 = 5
t = 4
3x+10y=-12|*2
8x+4y=-7|*(-5)
6x+20y=-24
-40x-20y=35
-34x=11
x=-11/34
x=-0,323
3x+10y=-12
10y=-12-3x
y=-1,2-0,3x
y=-1,2-0,3*(-11/34)
y=(3,3-40,8)/34=-37,5/34
y=-1,103
как то так)...
2[x+1]=3x
[x+1]=3x/2
x+1=3x/2
<span>1=x/2
x=2
</span>x+1=-3x/2
1=-2x
x=-1/2
<span>ответ -1/2;2
</span>2.[x^2+3]< 12
x^2+3<12
x^2+3>-12
x^2<9
x<span>∈(-3;3)
</span>
sin110=sin250
cos540=cos(360+180)=cos180=-1
cos290=cos(180+110)=-cos110
cos430=cos(360+70)=cos70
cos70=cos110
(sin ²110+cos ²110)/cos<span> ²(1440+180)
1/cos</span> ²1620=1/cos ²180=1