Дано: 2x^3, (xy)^2.
1) 2x^3 * (xy)^2=2x^3*x^2*y^2=2*x^5*y^2);
2) 2*(2x^3 *(xy)^2)=2*2*x^3*y^2);
3) (2x^3)^3 * (xy)^2 = 8x^9 * x^2 * y^2 = 8*x^11*y^2)
4) 3*(2x^3) * ((xy)^2)^2 = 6x^3 * x^4 * y^4 = 6x^7*y^4)
5) 3*(2x^3)^2 * (xy)^2 = 3*8x^6 * x^2 * y^2 = 24*x^8*y^2
![\left \{ {{a+3b=2} \atop {2a+3b=7}} \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Ba%2B3b%3D2%7D%20%5Catop%20%7B2a%2B3b%3D7%7D%7D%20%5Cright.)
2a+3b=7
b=(-2a+7)/3
a+3b=2
a+3*((-2a+7)/3)=2
a+(-2a+7)-2=0
-a+7-2=0
a=5
2a+3b=7
2*5+3b=7
b=-3/3
b=-1
Ответ: a=5; b=-1.
P = 2(a + b) = 22
S = a*b = 30
a + b = 11
a*b = 30
b*(11 - b) = 30
a = 11 - b
11b - b^2 - 30 = 0
b^2 - 11b + 30 = 0
D = 121 - 120 = 1
b1 = (11 + 1)/2 = 12/2 = 6
b2 = (11 - 1)/2 = 10/2 = 5
a1 = 11 - b1 = 11 - 6 = 5
b1 = 6
a2 = 11 - b2 = 11 - 5 = 6
b2 = 5
Ответ
5; 6
= √ 32 * √ 2 - √ 32 * √ 5 - 4 √ 10 = √ 64 - √ 160 - 4√ 10 = 8 - 4√ 10 - 4 √ 10 =
= 8 - 8 √ 10